RF-CONCRETE Surfaces – Online Manual Version 5

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RF-CONCRETE Surfaces – Online Manual Version 5

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2.3.3 Two-Directional Reinforcement Meshes with k < 0

Two-Directional Reinforcement Meshes with k < 0

If the main axial forces N1 and N2 have different signs in a two-directional reinforcement mesh, a tension force is respectively obtained for the equilibrium of forces in the two reinforcement directions, as well as a compression force in the selected direction of the compressive strut.

Figure 2.16 Two-directional reinforcement in tension and compression

Rows 5 and 6 of Table IV (Figure 2.15) provide examples for this possible state of equilibrium.

However, for a wall subjected to both tension and compression, a compression strut may expectedly result in the direction γ and another one in the direction β for the selected direction of the concrete compression strut (arithmetic mean between the two reinforcement directions). This is exactly the case when the arithmetic mean in the diagram above is to the left of the zero crossing of the force distribution of Zy. However, this kind of equilibrium is not possible. The reinforcement of the conjugated direction is determined, that is, the value γ0y is used for the compression strut direction γ.

tan γ0y = -k · cot α 

This means that no force occurs in the second reinforcement direction y under the angle β. Row 7 in Table IV (Figure 2.15) shows an example of this equilibrium of forces. In the RF-CONCRETE Surfaces add-on module, such a state of equilibrium is reached when a compression force in the direction of the reinforcement direction y results for the routinely assumed direction of the compression strut (arithmetic mean between the directions of both reinforcement sets).

We have thus described all possible states of equilibrium for two-directional reinforcements.

Quick Overview of this Section

Quick Overview of this Section