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2.5.6 Shear Design
In the shear design, the applied tensile reinforcement is determined first.
From all reinforcement layers and directions, a total of 1.54 cm2/m of tension reinforcement can be applied. With this, the resisting shear force VRd,c without shear reinforcement is determined.
With the applied tensile reinforcement, the longitudinal reinforcement ratio ρl is determined:
In a 3D type of model (unlike a plate), an additional axial force can occur. It must be considered through the corresponding concrete longitudinal stress.
The factor k for considering the plate thickness is calculated as follows:
The following factors are also included in the design:
Factor of concrete longitudinal stress
k1 = 0.15
Concrete compressive strength for C30/37
fck = 30.0 N/mm2
Thus, the design shear resistance VRd,c without shear reinforcement can be determined according to Equation (6.2a):
The minimum value of the design shear resistance VRd,c without shear reinforcement is determined according to Equation (6.2b) from the minimum reinforcement ratio νmin:
Because the plate's design shear resistance VRd,c = 459.96 kN/m is greater than the applied shear force VEd = 259.726 kN/m, no shear reinforcement is required in the example.
Should the plate's shear resistance be insufficient, the program first checks if the maximum shear resistance of the concrete compression strut VRd,max is sufficient. VRd,max is determined with the minimum inclination of the compression strut θ. If the design shear resistance of the concrete compression strut is greater than the applied shear force VEd, the statically required shear reinforcement req asw can be determined. Then, the design for the shear reinforcement VRd,sy is carried out.