Answer:
With a normal suspension on a crane hook or on a lifting beam, the structural component will be able to move away under external horizontal loads. Similarly, the suspension on the crane will not provide support for internal forces occurring in the system.
Displaying systems that are actually unstable (because they are capable of movement) in a calculation program is not always easy. You should activate the supports on the crane eyes for X and Y (horizontal) and consider how horizontal forces resulting from uneven vertical loading (= rotation) can be absorbed.
However, the model can usually be calculated if the lifting beam is supported horizontally by a very small spring (see the model file).
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