公式 3

\begin{array}{l} ε = \sqrt{235 / f_{y}} = \sqrt{235 / 345} = 0.825 \\ λ_{1} = 9 \cdot ε = 9 \cdot 0.825 = 7.4 < \frac{c_{f}}{t_{f}} = 9.8 \\ λ_{2} = 10 \cdot ε = 10 \cdot 0.825 = 8.2 < \frac{c_{f}}{t_{f}} = 9.8 \\ λ_{3} = 14 \cdot ε = 14 \cdot 0.825 = 11.6 > \frac{c_{f}}{t_{f}} = 9.8 \end{array}

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