Formula 5

\begin{array}{l} σ_{l} = \frac{2 \cdot 103, 25^{2}}{109, 55^{2} - 103, 25^{2}} = 15, 9 N / mm ² \\ {\bar{σ}}_{t} = \frac{2 \cdot 103, 25}{109, 55 - 103, 25} = 32, 8 N / mm ² \\ {\bar{σ}}_{r} = \frac{- 2 \cdot 103, 25}{109, 55 103, 25} = - 1, 0 N / mm ² \end{array}

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