Formula 3

\begin{array}{l} z_{S, 1} = \frac{\frac{2.15 \cdot 0.30 \cdot 0.30}{2} + 4.70 \cdot 0.30 \cdot (\frac{4.70}{2} + 0.30) + 2.15 \cdot 0.30 \cdot (0.30 + 4.70 + \frac{0.30}{2})}{2.15 \cdot 0.30 \cdot 2 + 4.70 \cdot 0.30} = 2.65 m \\ y_{S, 1} = \frac{2.15 \cdot 0.30 \cdot \frac{2.15}{2} \cdot 2 + 4.70 \cdot 0.30 \cdot \frac{0.30}{2}}{2.15 \cdot 0.30 \cdot 2 + 4.70 \cdot 0.30} = 0.59 m \\ I_{y, 1} = 2.15 \cdot \frac{0.303}{12} \cdot 2 + 2.15 \cdot 0.30 \cdot (\frac{2.65 - 0.30}{2}) ² \cdot 2 + 0.30 \cdot \frac{4.703}{12} + 4.70 \cdot 0.30 \cdot (0.00) ² = 10.668 m^{4} \\ I_{z, 1} = 0.30 \cdot \frac{2.153}{12} \cdot 2 + 2.15 \cdot 0.30 \cdot (\frac{2.15}{2} - 0.59) ² \cdot 2 + 4.70 \cdot \frac{0.303}{12} + 4.70 \cdot 0.30 \cdot (0.59 - \frac{0.30}{2}) ² = 1.084 m^{4} \end{array}

Do you have any questions?