Minimum Natural Frequency According to DIN 1052

Minimum natural frequency according to DIN 1052

\frac{f_{e}^{2} \cdot 4}{π^{2}} = \frac{5 \cdot g}{384 \cdot w}

f_{e, \min, DIN} = \frac{5}{\sqrt{0, 8 \cdot w}} = \frac{5}{\sqrt{0, 8 \cdot 0.6}} = 7.2 Hz

f_e,min,DIN	Minimum natural frequency according to DIN 1052
w	Deflection
g	Acceleration of gravity

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