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000059

2024-01-16

Formula 4

\begin{array}{l} T_{M, d} = \frac{M_{\max, d}}{80} = \frac{102, 665 kNcm}{80} = 12.8 kNm \\ W_{t} = 11, 520 cm ³ \\ τ_{tor, d} = \frac{1, 280 kNcm}{11, 520 cm ³} = 0.11 kN / cm ² \\ τ_{d} = 1.5 \cdot \frac{V_{d}}{k_{cr} \cdot b \cdot h} = 0.12 kN / cm ² \end{array}

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