Formula 9

\begin{array}{l} F_{T, 2, Rd} = \frac{2 \cdot M_{pl, 2, Rd} n \cdot {ΣF}_{t, Rd}}{m n} \\ where \\ M_{pl, 2, Rd} = \frac{0.25 \cdot l_{eff, 2} \cdot t_{f} ² \cdot f_{y}}{γ_{M 0}} \\ {ΣF}_{t, Rd} = ΣTension resistance of bolts \\ n = e_{\min} < 1.25 \cdot m \\ e_{\min} = 35 mm for the outer bolt row \\ e_{\min} = 75 mm for the inner bolt row \\ m = 39.8 mm for the outer bolt row \\ m = 62.6 mm for the inner bolt row \\ {ΣF}_{t, Rd} = \frac{2 \cdot k_{2} \cdot f_{ub} \cdot A_{S}}{γ_{M 2}} = \frac{2 \cdot 0.9 \cdot 100 \cdot 3.53}{1.25} = 508.32 kN \\ The punching force has been checked but is not governing . \\ M_{pl, 2, Rd} = \frac{0.25 \cdot 15.0 \cdot 2.52 \cdot 23.5}{1.0} = 550.78 kNcm for the outer bolt row \\ M_{pl, 2, Rd} = \frac{0.25 \cdot 41.63 \cdot 2.52 \cdot 23.5}{1.0} = 1, 528.60 kNcm for the inner bolt row \\ F_{T, 2, Rd} = \frac{2 \cdot 550.78 3.5 \cdot 508.32}{3.98 3.5} = 385.12 kN for the outer bolt row \\ F_{T, 2, Rd} = \frac{2 \cdot 1, 528.60 7.5 \cdot 508.32}{6.26 7.5} = 499.24 kN for the inner bolt row \end{array}

Do you have any questions?