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42x

000426

2024-01-16

Formula 15

ρ_{2} = \frac{{\bar{λ}}_{p 2} - 0.055 \cdot (3 ψ)}{{\bar{λ}}_{p 2}^{2}} = \frac{3.588 - 0.055 \cdot (3 1)}{3 . 588^{2}} = 0.262 < 1

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