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66x

000594

2024-01-16

Formula 4

\begin{array}{l} y = 2 \cdot 10 = 20 m \\ A_{fr} = 2 \cdot (30 m - 20 m) \cdot 4 m 2 \cdot (30 m - 20 m) \cdot 5.22 m = 184.4 m ² \\ q_{p (ze)} = 2.1 \cdot q_{b} \cdot {(\frac{z}{10})}^{0.24} = 2.1 \cdot 0.39 kN / m ² \cdot {(\frac{5.5 m}{10})}^{0.24} = 0.711 kN / m ² \\ F_{fr} = 0.04 \cdot 0.711 kN / m ² \cdot 184.4 m ² = 5.245 kN \end{array}

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