Formula 4

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kser = 10 · ρm1.5 · d0.880 = 10 · (350 kg/m³)1.5 · (4.2 mm)0.880 = 2,579.95 N/mmuK,DF = h · sin α = 2,750 mm · sin (0.0195) = 0.94 mmα = F · h · 180KDF · π = 1,000 N · 2,750 mm · 1808.06 · 109 · π = 0.0195°KDF = l2 · kser2 = (2,500 mm)² · 2.579.95 N/mm2 = 8.06 · 109

Formula 4

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