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1 - 10 of 1910

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  • Answer

    In order to be able to assign an eccentricity to a member, it is usually necessary to create it before setting the member.

    Another approach is shown in the following example. First, the eccentricity is created and then assigned to an existing member via its interface:


    '---------------------
    Sub SetEccentricity()
    '---------------------

    Dim model As RFEM5.model
    Set model = GetObject(, "RFEM5.Model")
    model.GetApplication.LockLicense

    On Error GoTo e

    Dim iModData As RFEM5.iModelData
    Set iModData = model.GetModelData

    '   create eccentricity
    Dim eccens(0 To 0) As RFEM5.MemberEccentricity
    eccens(0).No = 1
    eccens(0).Comment = "test eccentricity"

    eccens(0).ReferenceSystem = LocalSystemType

    eccens(0).Start.X = 0
    eccens(0).Start.Y = 0
    eccens(0).Start.Z = 0

    eccens(0).End.X = 0
    eccens(0).End.Y = 0
    eccens(0).End.Z = 0

    eccens(0).HingeAtEndNode = False
    eccens(0).HingeAtStartNode = False

    eccens(0).HorizontalAlignment = Middle
    eccens(0).VerticalAlignment = Bottom

    eccens(0).TransverseOffset = True
    eccens(0).ReferenceObjectNo = 2
    eccens(0).ReferenceObjectType = MemberObject
    eccens(0).HorizontalAxisOffset = Middle
    eccens(0).VerticalAxisOffset = Top

    eccens(0).StartAdjoiningMembersOffset = False
    eccens(0).EndAdjoiningMembersOffset = False

    iModData.PrepareModification
    iModData.SetMemberEccentricities eccens
    iModData.FinishModification

    '   add eccentricity to member
    Dim iMem As RFEM5.IMember
    Set iMem = iModData.GetMember(1, AtNo)

    Dim mem As RFEM5.Member
    mem = iMem.GetData

    mem.EccentricityNo = 1

    iModData.PrepareModification
    iMem.SetData mem
    iModData.FinishModification


    e:      If Err.Number <> 0 Then MsgBox Err.Description, , Err.Source

    model.GetApplication.UnlockLicense

    End Sub


    Member eccentricities can only be transferred as a field; for this purpose, a field with only one element has been created. In the attached image, the individual elements are itemized with reference to the graphical elements.

  • Answer

    Unfortunately, it is not. Dlubal Software requires specialized knowledge in the field of structural analysis; therefore, the student version is only available to students of technical colleges and universities teaching structural analysis, engineering mechanics, and similar subjects.

  • Answer

    The trapezoidal sheet is modeled as an orthotropic surface. In the default setting, the arches of the trapeziodal sheet are in the x directions, which is the same direction of the IPE 120 beams.

    If you set the orthotropy direction to 90 degrees, that is, perpendicular to the beams, the moments will increase. If the sheet metal arches are perpendicular to the beams, the stiffness in the second direction is very small, so the load is transferred first between the IPE 120 beams.

  • Answer

    The value of the coordinates must lie in the range from -100,000 m to 100,000 m.

  • Answer

    The load cases marked in red, such as LC4 in the image, cannot be designed: Such a load case contains either no loading or imperfections only. When selecting the load case, a corresponding warning appears.
  • Answer

    This setting is used to reduce the effective concrete tensile strength fct,eff. If you expect the crack formation in the first 28 days, you should reduce the effective tensile strength of concrete fct,eff according to EN 1992‑1‑1, 7.3.2 (2). You can enter the corresponding reduction factor. The German National Annex recommends to use fct,eff = 0.50 ⋅ fctm (28d). If you cannot determine a definite point of time for crack formation within the first 28 days, a tensile strength of at least 3 N/mm² for normal concrete should be assumed in accordance with the German National Annex.
  • Answer

    Some browsers may initially block the download of the authorization file because they recognize it as a threat. In this case, you can still download the file in the browser. To do this, ignore the blocking in the menu. The image shows the corresponding option of the Microsoft Edge browser.

  • Answer

    Yes this is possible and can be done by adding in an opening in the slap and then place a thicker slab within the opening. Then the column would connect to this thicker slap along with an average region and FE mesh refinement to eliminate singularities. This can be designed within the RF-CONCRETE Surfaces add-on module. 


    The punching shear design module RF-PUNCHING Pro does not have the ACI or CSA standards implemented so the solution above is an alternative to this.

  • Answer

    By selecting the "End Prestress" load type in the load definition of RFEM 5, the program increases the load internally until the axial force is equal to the prestress force.

    You can display the internal load by displaying the continuous deformation load in the x-direction in the Results navigator.


    This results in a deformation of -0.00168 for the end prestress of the structural system. With the modulus of elasticity of the member and the cross-section of it, you can also determine the initial prestress:

    V = ɛ * E * A = 0.00168 * 21,000 * 7.07 = 249.4 kN 


  • Answer

    Although member end forces are typically used for connection design (see FAQ 4918), there may be the scenario that you're interested in the total internal forces at a particular node where several members are framing into this point at various angles. The program does not give internal force result information at nodes by default.  

    The best option is to create a result beam where you can select which members to consider for the internal force summation. Result beams do not add any stiffness to the model and are used purely as a result interpretation tool (see KB 1406). You can view internal forces on result beams as you would any other member which the member end force can provide the force summary at a particular node. 

    Please note, result beams internally create a perpendicular plane at each point along the member length and at both ends to determine which forces shall be integrated in the results. This works well for all elements which do not lie directly in the perpendicular plane to the result beam. For any elements that are directly perpendicular, a very small offset must be applied to the element so it's no longer perfectly perpendicular for the result beam to also capture its results. 

1 - 10 of 1910

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