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I would like to calculate a traverse hanging on a crane. Why does the program always show me an instability when calculating?


In the case of a normal suspension on crane hooks or cross members, the structural component will be able to move away under external horizontal loads. Likewise, the suspension on the crane will not represent a support for internal forces that occur in the structure.

It is not always easy to display actually unstable moving systems in a calculation program. It is recommended to release the supports at the crane eyes for X and Y (horizontal) and consider how horizontal forces resulting from an uneven vertical loading (= torsion) can be absorbed. 

However, the model can usually be calculated if the traverse is supported horizontally with a very small spring (see model file).


traverse hanging systems crane girder



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