I am trying to compare a design for flexural buckling according to the equivalent member method and internal forces according to the linear static analysis with a stress calculation according to the second-order analysis including imperfections and obtain very large differences. What could be the reason? 

Answer

While the influence of imperfection increases significantly with increasing axial force and the design increases exponentially, it only increases linearly in the equivalent-member design to the increase of the axial force. Therefore, very strongly and very weakly loaded systems usually deviate more strongly in the ratios of the linear static analysis by means of equivalent member methods compared to second-order analysis by means of stress design.

Keywords

Differences Equivalent member design Stress analysis 1st Order Theory 2nd Order Theory

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