8 November 2019

FAQ 004200 EN

Thomas Günthel




Why are there no resultant support forces for result combinations?


For a resultant, a concrete combination of loads is required, which result combinations cannot provide.

The problem is apparent in the following example. A single-span beam is loaded with three different load cases. For the support at node 1, the result envelope of the 6 possible load combinations gives a maximum P-Z of 11.25 kN based on the result of CO2 (see Figure 01). The support at node 2 has a maximum P-Z of 12 kN based on the result of CO1. The resultant of 23.25 kN, however, does not exist in any of the involved load combinations and is therefore too large (maximum LK 1 and LK 2 with 22.5 kN).

The situation is similar to the pure result combination of the load cases which have the same maximum values P-Z of the nodal supports 1 and 2. However, it is not apparent here that a resultant would give incorrect results.

For this reason, a resultant is not used for result combinations, since the results can be incorrect.


Resultant Result combination


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