FAQ 002238 EN-US

Modeling | Loading

How are unloaded bars handled by the load generator?

Answer

In both cases shown in Figure 1, the total load is 51 kN in global X. The problem is the different distributions in both cases. In variant A, the green loads are larger and the red smaller and in variant B it is the other way round. The biggest problem in variant A is that the red loads are strangely the same size as in the area above, but where there are still the intermediate bars (green load). The problem here is the yellow bordered area. Internally, the load of the entire surface is first calculated (51 kN) and then the closed cells (plane completely framed by bars) are subtracted from it. Since the yellow framed surface does not represent a cell (the limiting rod between nodes 20 and 36 is missing), there is a special case here. The generator proceeds as follows. Removing the horizontal bars creates a large fictitious cell between nodes 23,760,36 and 20. By the already mentioned missing cell it is assumed that the outer bars all have a constant load (here 1.6 and 1.0 kN / m) and the remaining load is distributed to the inner rods. As a result, in variant A the green load is higher and the red loads smaller. To modify this distribution, the load generator has the following option "Apply all bars", as shown in Figure 2. This option creates the missing cell internally and distributes the loads according to Variant B. In our blog, there is one more interesting post: http: //www.dlubal.com/blog/9034/dlubal-rfem-5-rstab-8-behandlung-von-unbelasteten-staben-bei-derlastlastierung

Keywords

load distribution load generators all bars

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