FAQ 003547 EN

2 September 2019

# SHAPE-THIN calculates a very small shear area. What is the reason for this?

The shear area is calculated as follows:

${\mathrm A}_{\mathrm y}\;=\;\frac{{\mathrm I}_{\mathrm z}^2}{\int_{\mathrm A^\ast}\left({\displaystyle\frac{{\mathrm S}_{\mathrm z}}{\mathrm t^\ast}}\right)^2\operatorname d\mathrm A^\ast}$

${\mathrm A}_{\mathrm z}\;=\;\frac{{\mathrm I}_{\mathrm y}^2}{\int_{\mathrm A^\ast}\left({\displaystyle\frac{{\mathrm S}_{\mathrm y}}{\mathrm t^\ast}}\right)^2\operatorname d\mathrm A^\ast}$

Where:

 Iz or Iy: second moment of area in relation to the axis z or y Sz or Sy: first moment of area in relation to the axis z or y t*: effective element thickness for shear transfer A*: surface area based on effective shear thickness t*

The effective element thickness for shear transfer t* has a significant influence on the shear area. Therefore, the defined effective element thickness for shear transfer t* (Figure 1) of the elements should be checked.