1502x
003547
2021-06-14

Question

SHAPE‑THIN calculates a very small shear area. Why?


Answer:

The shear area is calculated as follows:

${\mathrm A}_{\mathrm y}\;=\;\frac{{\mathrm I}_{\mathrm z}^2}{\int_{\mathrm A^\ast}\left({\displaystyle\frac{{\mathrm S}_{\mathrm z}}{\mathrm t^\ast}}\right)^2\operatorname d\mathrm A^\ast}$

${\mathrm A}_{\mathrm z}\;=\;\frac{{\mathrm I}_{\mathrm y}^2}{\int_{\mathrm A^\ast}\left({\displaystyle\frac{{\mathrm S}_{\mathrm y}}{\mathrm t^\ast}}\right)^2\operatorname d\mathrm A^\ast}$

where

Iz or Iy
is the second moment of area in relation to the axis z or y,
Sz or Sy
is the first moment of area in relation to the axis z or y,
t*
is the effective element thickness for the shear transfer,

A*

is the surface area based on the effective shear thickness t*.

The effective element thickness for the shear transfer t* has a significant influence on the shear area. Therefore, the defined effective element thickness for the shear transfer t* (Image 01) of the elements should be checked.