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FAQ 004659 | When defining friction, there are two interaction relations. How do they differ? Should not be there an identical result when defining the same friction coefficients?
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Question
When defining friction, there are two interaction relations. How do they differ? Should not be there an identical result when defining the same friction coefficients?Answer
The definition of the forces is specified in the corresponding dialog box (see Figure 01). The maximum friction force depends on the load in the Y‑direction or Z‑direction. Depending on which interaction formula is used, there are different friction forces as a result.
Example
A support should transfer the force in the global X-direction by friction. The friction coefficient is 0.1 for all directions. The support force PY is 5 kN and the support force PZ is 10 kN.
This results in the following maximum support force in the X-direction for the "Friction PY' PZ' ..." nonlinearity:
${\mathrm P}_{\mathrm X,\max}\;=\;{\mathrm\mu}_{\mathrm X}\;\cdot\;\sqrt{\;{\mathrm P}_{\mathrm Y}^2\;+\;{\mathrm P}_{\mathrm Z}^2}\\{\mathrm P}_{\mathrm X,\max}\;=\;0.1\;\cdot\;\sqrt{\;5^2\;+\;10^2}\;=\;1.118\;\mathrm{kN}$
For the second option "Friction PY'+ PZ'...," the maximum support force results in:
${\mathrm P}_{\mathrm X,\max}\;=\;{\mathrm\mu}_{\mathrm{XY}}\;\cdot\;\left|{\mathrm P}_{\mathrm Y}\right|\;+\;{\mathrm\mu}_{\mathrm{XZ}}\;\cdot\;\left|{\mathrm P}_{\mathrm Z}\right|\\{\mathrm P}_{\mathrm X,\max}\;=\;0.1\;\cdot\;5\;+\;0.1\;\cdot\;10\;=\;1.500\;\mathrm{kN}$
While the resulting support force is used to determine the friction force in the first option, the forces are added linearly in the second option.
Thus, the structural system shown in Figure 02 becomes unstable as of the force > 1.118 kN for the first option, and as of the force > 1.500 kN for the second option.
Keywords
Dlubal FAQ Friction Interaction Frequently Asked Question FAQ about Dlubal Question and Answer about Dlubal
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