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Sonja von Bloh, M.Sc.

2020-11-20

Load Distribution on Members for Angular Axis Method

How is the load distributed to the members in the angular axis method if the members are excluded from the load application?

Answer:

An area load of 1 kN/m² delimited by Node 1 to Node 4 is only applied to Member 3 (Image 01).

1 Surface Load

The entries carried out in the load generator are shown in Image 02. There is no correction of the distribution according to the moment equilibrium (Image 03).

2 Settings for Converting Surface Loads to Member Loads

3 Settings for Load Generation via Plane

The generated member load is shown in Image 04. This is calculated as follows:

q = 1.00 kN / m^{2}

h_{1} = 4.00 m

h_{2} = 6.00 m

b_{tot} = 12.00 m

α = \arctan (\frac{h_{2} - h_{1}}{b_{tot}}) = \arctan (\frac{6.000 - 4.000}{12.000}) = 9.46 °

b_{1} = \tan (α) \cdot h_{1} = \tan (9.46 °) \cdot 4.000 = 0.667 m

l_{1} = \sqrt{b_{1}^{2} + h_{1}^{2}} = \sqrt{0 . 667^{2} + 4 . 000^{2}} = 4.055 m

l_{2} = \cos (α) \cdot h_{2} = \cos (9.46 °) \cdot 6.000 = 5.918 m

A_{R} = \frac{b_{1} \cdot h_{1}}{2} = \frac{0.667 \cdot 4.000}{2} = 1.335 m^{2}

l_{tot} = \sqrt{b_{tot}^{2} + {(h_{2} - h_{1})}^{2}} = \sqrt{12 . 000^{2} + {(6.000 - 4.000)}^{2}} = 12.166 m

q	Area load
A_R	Remaining area (marked in red in Image 04)
q_c	Constant load component on the loaded member
q₂	Member load Node 2
q₅	Member load Node 5
q₄	Member load Node 4

Calculation of Member Load

4 Generated Member Load from Surface Load

Author

Ms. von Bloh provides technical support for our customers and is responsible for the development of the SHAPE‑THIN program as well as steel and aluminum structures.

Downloads

RFEM Model File

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