102x
009948
2023-08-31

VE0048 | Uniaxial Bending with Pressure

Description

A structure made of I-profile is fully fixed on the left end and embedded into the sliding support on the right end. The structure consists of two segments according to the following sketch. The self-weight is neglected in this example. Determine the maximum deflection of the structure uz,max, the bending moment My on the fixed end, the rotation φ2,y of the segment 2 and the reaction force RBz by means of the geometrically linear analysis and the second-order analysis. The verification example is based on the example introduced by Gensichen and Lumpe (see the reference).

Material Steel Modulus of Elasticity E 210000.000 MPa
Poisson's Ratio ν 0.300 -
Geometry Structure Segment Length 1 L1 6.000 m
Segment Length 2 L2 1.200 m
Cross-section Height h 400.000 mm
Width b 180.000 mm
Web Thickness s 10.000 mm
Flange Thickness t 14.000 mm
Load Axial Force Fx 100.000 kN
Transverse Force Fz 0.500 kN

Analytical Solution

Geometrically Linear Analysis

Geometrically linear analysis is carried out at first. In this case, the axial force Fx is not taken into account. The problem can be then solved as well as a cantilever of the length L1 loaded only by the transverse force Fz. The maximum deflection uz,max can be calculated using Mohr's integral and results into expression:

The bending moment on the fixed end can be calculated according to the following formula:

The rotation of the segment 2 φ2,y is calculated from the geometric condition as follows:

The reaction force in the sliding joint RBz considering the zero effect of the axial force Fx can be obtained from the free body diagram shown in the following sketch.

Second-order Analysis

Because of the nonnegligible effect of the axial force Fx the second-order analysis should be considered. Thus the axial force Fx is taken into account and produces another contribution to the bending moment. The problem can be described by the free body diagram of the segments according to the sketch. The unknown reaction forces can be obtained from the equilibrium equations and then the bending moment formula can be written.

The solution can be found by the Euler-Bernoulli differential equation.

Considering boundary conditions the solution on the differential equation can be found and maximum deflection of the structure calculated.

The bending moment on the fixed end can be calculated according to the following formula:

The rotation of the segment 2 φ2,y is calculated from the geometric condition as follows:

The reaction force in the sliding joint RBz results:

It is obvious that the influence of the axial force Fx is considerable. The total deflection of the structure under the prescribed loading in case of the second-order analysis is approximately 18 % greater than in case of geometrically linear analysis. The comparison of the geometrically linear analysis and the second-order analysis is shown in the graph, considering the ratio of the loading forces Fz = Fx/200. It is obvious that the difference between these analysis is more considerable when the loading is grater. The second-order analysis solution is approaching the horizontal asymptote. The numerical solution gives the value of the horizontal asymptote Fx,cr = 650.873 kN.

RFEM and RSTAB Settings

  • Modeled in RFEM 5.05 and RSTAB 8.05 and RFEM 6.01, RSTAB 9.01
  • The number of elements is 2 (one element per member)
  • The number of increments is 5
  • Isotropic linear elastic material model is used
  • The structure is modeled using members
  • Shear stiffness of the members is neglected

Results

Geometrically Linear Analysis Analytical Solution RFEM 6 Ratio RSTAB 9 Ratio
uz,max [mm] 0.743 0.743 1.000 0.743 1.000
My(0) [kNm] 3.000 3.000 1.000 3.000 1.000
φ2,y [mrad] 0.619 0.619 1.000 0.619 1.000
RBz [kN] 0.000 0.000 - 0.000 -
Geometrically Linear Analysis Analytical Solution RFEM 5 Ratio RSTAB 8 Ratio
uz,max [mm] 0.743 0.743 1.000 0.743 1.000
My(0) [kNm] 3.000 3.000 1.000 3.000 1.000
φ2,y [mrad] 0.619 0.619 1.000 0.619 1.000
RBz [kN] 0.000 0.000 - 0.000 -
Second-order Analysis Analytical Solution RFEM 6 Ratio RSTAB 9 Ratio
uz,max [mm] 0.878 0.878 1.000 0.878 1.000
My(0) [kNm] 3.527 3.527 1.000 3.527 1.000
φ2,y [mrad] 0.732 0.732 1.000 0.732 1.000
RBz [kN] -0.073 -0.073 1.000 -0.073 1.000
Second-order Analysis Analytical Solution RFEM 5 Ratio RSTAB 8 Ratio
uz,max [mm] 0.878 0.878 1.000 0.878 1.000
My(0) [kNm] 3.527 3.527 1.000 3.527 1.000
φ2,y [mrad] 0.732 0.732 1.000 0.732 1.000
RBz [kN] -0.073 -0.073 1.000 -0.073 1.000

References
  1. LUMPE, G. and GENSITEN, V. Evaluation of Linear and Nonlinear Member Analysis in Theory and Software: Test examples, causes of failure, detailed theory. Ernest.