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FAQ 003547 EN-US

09/02/2019

# SHAPE-THIN calculates a very small shear area. What is the reason for this?

The shear area is calculated as follows:

${\mathrm A}_{\mathrm y}\;=\;\frac{{\mathrm I}_{\mathrm z}^2}{\int_{\mathrm A^\ast}\left({\displaystyle\frac{{\mathrm S}_{\mathrm z}}{\mathrm t^\ast}}\right)^2\operatorname d\mathrm A^\ast}$

${\mathrm A}_{\mathrm z}\;=\;\frac{{\mathrm I}_{\mathrm y}^2}{\int_{\mathrm A^\ast}\left({\displaystyle\frac{{\mathrm S}_{\mathrm y}}{\mathrm t^\ast}}\right)^2\operatorname d\mathrm A^\ast}$

These include:

 I z or I y : 2nd-order moment of area in relation to the axis z or y S z or S y : 1st degree moment of area in relation to the axis z or y t *: effective element thickness for shear transfer A *: Surface Area Based on Effective Shear Thickness t *

The effective element thickness for shear transfer t * has a significant influence on the shear area. Therefore, the defined effective element thickness for shear transfer t * (Figure 1) of the elements should be checked.